Python math.floor() rounding with precision down-to n places

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import math


def floor_precised(number, precision):
    power = math.pow(10, precision)
    return math.floor(number * power) / power


print(floor_precised(5, 0))    # 5.0
print(floor_precised(5.0, 0))  # 5.0
print(floor_precised(.5, 0))   # 0.0

print(floor_precised(1.1234, 0))  # 1.0
print(floor_precised(1.1234, 1))  # 1.1
print(floor_precised(1.1235, 2))  # 1.12
print(floor_precised(1.1235, 3))  # 1.123

print(floor_precised(-1.1234, 0))  # -2.0
print(floor_precised(-1.1234, 1))  # -1.2
print(floor_precised(-1.1234, 2))  # -1.13
print(floor_precised(-1.1234, 3))  # -1.124

print(floor_precised(1234, -1))  # 1230.0
print(floor_precised(1234, -2))  # 1200.0
print(floor_precised(1234, -3))  # 1000.0

print(floor_precised(5_000.000_001, 0))   # 5000.0
print(floor_precised(5_000.000_001, 6))   # 5000.000001
print(floor_precised(5_000.000_001, -3))  # 5000.0