Java - convert long to binary String with leading zeros

Short solution:

long number = 10_000_000_000L;

String binaryString = Long.toBinaryString(number);
String withLeadingZeros = String.format("%64s", binaryString).replace(' ', '0');

// 1001010100000010111110010000000000
System.out.println(binaryString);

// 0000000000000000000000000000001001010100000010111110010000000000
System.out.println(withLeadingZeros);

In java simples way to convert long to binary String with leading zeros is to use Long.toBinaryString(number) and String.format() method. 
Note that as first param in String format we pass number of leading spaces and we replace all spaces with 0. Usually we use 32 or 64 padding zeros.

1. Convert long to binary String with leading zeros

public class Example1 {

    public static void main(String[] args) {

        long number = 8;

        String binary = Long.toBinaryString(number);
        String padding = String.format("%8s", binary).replace(' ', '0');
        String numberPadding = String.format("%4s", number);

        System.out.println("long | binary");
        System.out.println(numberPadding + " - " + padding);
    }
}

Output:

long | binary
   8 - 00001000

2. Convert large long to binary String - 64 length padding

public class Example2 {

    public static void main(String[] args) {

        long number = 31L * Integer.MAX_VALUE;

        String binary = Long.toBinaryString(number);
        String padding = String.format("%64s", binary).replace(' ', '0');

        System.out.println("long:");
        System.out.println(number);
        System.out.println("binary (64 length padding):");
        System.out.println(padding);
    }
}

Output:

long:
66571993057
binary (64 length padding):
0000000000000000000000000000111101111111111111111111111111100001

3. Print long to binary - between 0 and 8 with leading zeros

public class Example3 {

    public static void main(String[] args) {

        System.out.println("long | binary");

        for (long i = 0; i <= 8; i++) {

            String binary = Long.toBinaryString(i);
            String padding = String.format("%8s", binary).replace(' ', '0');
            String intPadding = String.format("%4s", i);

            System.out.println(intPadding + " - " + padding);
        }
    }
}

Output:

long | binary
   0 - 00000000
   1 - 00000001
   2 - 00000010
   3 - 00000011
   4 - 00000100
   5 - 00000101
   6 - 00000110
   7 - 00000111
   8 - 00001000

Merged questions

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