EN
MySQL - find row with null value in one of many columns
0
points
In this article, we would like to show you how to find rows with NULL
value in one of many columns in MySQL.
Quick solution:
SELECT *
FROM `table_name`
WHERE `column1` IS NULL OR `column2` IS NULL OR `columnN` IS NULL;
SELECT *
FROM `table_name`
WHERE `column1`+`column2`+`columnN` IS NULL;
SELECT *
FROM `table_name`
WHERE CONCAT(`column1`, `column2`, `columnN`) IS NULL;
Practical example
To show how to find rows with NULL
value in one of many columns, we will use the following table:
Note:
At the end of this article you can find database preparation SQL queries.
Example 1 - IS NULL
& OR
In this example, we will select rows from users
table with NULL
value in email
OR
department_id
column.
Query:
SELECT *
FROM `users`
WHERE `email` IS NULL OR `department_id` IS NULL;
Result:
Example 2 - +
& IS NULL
In this example, we will select rows from users
table with NULL
value in email
or department_id
column using +
operator.
Query:
SELECT *
FROM `users`
WHERE `email`+`department_id` IS NULL;
Result:
Example 3 - CONCAT()
function
In this example, we will select rows from users
table with NULL
value in email
or department_id
column using CONCAT()
function.
Query:
SELECT *
FROM `users`
WHERE CONCAT(`email`, `department_id`) IS NULL;
Result:
Database preparation
create_tables.sql
file:
CREATE TABLE `users` (
`id` INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`name` VARCHAR(50) NOT NULL,
`surname` VARCHAR(50) NOT NULL,
`email` VARCHAR(100),
`department_id` INT(10) UNSIGNED,
`salary` DECIMAL(15,2) NOT NULL,
PRIMARY KEY (`id`)
);
insert_data.sql
file:
INSERT INTO `users`
( `name`, `surname`, `email`, `department_id`, `salary`)
VALUES
('John', 'Stewart', 'john@email.com', 1, '3512.00'),
('Chris', 'Brown', 'chris@email.com', 2, '1344.00'),
('Kate', 'Lewis', NULL, 3, '6574.00'),
('Ailisa', 'Gomez', 'ailisa@email.com', 2, '6500.00'),
('Gwendolyn', 'James', NULL, NULL, '4200.00'),
('Simon', 'Collins', NULL, 4, '3320.00'),
('Taylor', 'Martin', NULL, NULL, '1500.00'),
('Andrew', 'Thompson', 'andrew@email.com', NULL, '2100.00');