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MS SQL Server - IIF() function example
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In this article, we would like to show you IIF()
function example in MS SQL Server.
Quick solution:
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SELECT IIF(condition, if_true, if_false);
In this example, we will check two conditions, the first one will return true, and the second one will return false.
Query:
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SELECT IIF(1000 > 1, 'condition1_true', 'condition1_false') AS 'condition1_check';
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SELECT IIF(1000 < 1, 'condition2_true', 'condition2_false') AS 'condition2_check';
Result:

To show you how IIF()
function works, we will use the following table:

Note:
At the end of this article you can find database preparation SQL queries.
In this example, we will display salary
column from users
table and salary_information
which is created with IIF()
function.
Query:
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SELECT
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[salary],
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IIF([salary] > 6000, 'high_salary', 'average_salary') AS 'salary_information'
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FROM [users];
Result:

create_tables.sql
file:
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CREATE TABLE [users] (
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[id] INT IDENTITY(1,1),
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[name] VARCHAR(50) NOT NULL,
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[surname] VARCHAR(50) NOT NULL,
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[department_id] INT,
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[salary] DECIMAL(15,2) NOT NULL,
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PRIMARY KEY ([id])
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);
insert_data.sql
file:
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INSERT INTO [users]
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( [name], [surname], [department_id], [salary])
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VALUES
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('John', 'Stewart', 1, '3512.00'),
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('Chris', 'Brown', 2, '1344.00'),
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('Kate', 'Lewis', 3, '6574.00'),
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('Ailisa', 'Gomez', NULL, '6500.00'),
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('Gwendolyn', 'James', 2, '4200.00'),
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('Simon', 'Collins', 4, '3320.00'),
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('Taylor', 'Martin', 2, '1500.00'),
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('Andrew', 'Thompson', NULL, '2100.00');