EN
Bash - get location origin from given URL
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In this article, we would like to show you how to get location origin from given URL in Bash.
Quick solution:
xxxxxxxxxx1
echo 'https://dirask.com:8080/about' | awk 'match($0,/^[a-z]+:\/\/(www\.)?([^?#/]+)/,g){print g[2]}'
In this solution, we use match() function that lets to use regular expression with groups support.
xxxxxxxxxx1
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echo 'https://dirask.com:8080/about' | awk 'match($0,/^[a-z]+:\/\/(www\.)?([^?#/]+)/,g){print g[2]}'4
echo 'https://www.dirask.com:8080/about' | awk 'match($0,/^[a-z]+:\/\/(www\.)?([^?#/]+)/,g){print g[2]}'Output:
xxxxxxxxxx1
dirask.com:80802
dirask.com:8080xxxxxxxxxx1
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function get_origin() {4
echo "$1" | awk 'match($0,/^[a-z]+:\/\/(www\.)?([^?#/]+)/,g){print g[2]}'5
}6
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# Usage example 1:9
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get_origin 'https://dirask.com:8080/about'11
get_origin 'https://www.dirask.com:8080/about'12
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# Usage example 2:15
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origin_1="$(get_origin 'https://dirask.com:8080/about')"17
origin_2="$(get_origin 'https://www.dirask.com:8080/about')"18
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echo $origin_120
echo $origin_2Output:
xxxxxxxxxx1
dirask.com:80802
dirask.com:80803
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dirask.com:80805
dirask.com:8080
