TypeScript - create new Record<Key, Value>() using constructor (new operator)

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interface RecordConstructor {
    <K extends keyof any, V>(object?: Record<K, V>): Record<K, V>;
    new <K extends keyof any, V>(object?: Record<K, V>): Record<K, V>;
}

const Record: RecordConstructor = Object as RecordConstructor;


// Usage example:

const r1 = Record<string, number>();
const r2 = Record<string, number>({id: 1});

const r3 = new Record<string, number>();
const r4 = new Record<string, number>({id: 1});

const r5: Record<string, number> = {id: 1} ;
const r6: Record<string, number> = Record<string, number>({id: 1});
const r7: Record<string, number> = new Record<string, number>({id: 1});


// Constructor test:

const source = {id: 1};

const object1 = new Object();
const object2 = new Object(source);

const record1 = new Record<string, number>();
const record2 = new Record<string, number>(source);

console.log(object1 === source);  // false
console.log(object2 === source);  // true
console.log(record1 === source);  // false
console.log(record2 === source);  // true


// ------------------------------------------------------------------

// See also:
//
//     1. https://dirask.com/snippets/TypeScript-create-new-Record-Key-Value-using-constructor-new-operator-jEwK9D