TypeScript - is it possible to create object using new Record<Key, Value>() syntax?

You should define generic interface and contructor for Record<K, V>.

You can use this approach:

interface RecordConstructor {
    <K extends keyof any, V>(object: Record<K, V>): Record<K, V>;
    new <K extends keyof any, V>(object: Record<K, V>): Record<K, V>;
}

const Record: RecordConstructor = Object as RecordConstructor;


// Usage example:

const a                         = new Record<string, number>({name: 1});
const b: Record<string, number> =                            {name: 1} ;
const c: Record<string, number> = new Record<string, number>({name: 1});

const d                         =     Record<string, number>({name: 1});
const e: Record<string, number> =     Record<string, number>({name: 1});


// Constructor test:

const source = {name: 1};

const object1 = new Object(source);
const object2 = new Object(source);

const record1 = new Record<string, number>(source);
const record2 = new Record<string, number>(source);

console.log(object1 === source);  // true
console.log(object2 === source);  // true
console.log(record1 === source);  // true
console.log(record2 === source);  // true

Source: https://dirask.com/snippets/DnvYbD

See also

1. TypeScript - create new Record<Key, Value>() using constructor (new operator) - example 1

2. TypeScript - create new Record<Key, Value>() using constructor (new operator) - example 2