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Python - why is sorted list None?
1 answers
3 points
I am trying to sort a list in Python and it's NoneType, even tho merged variable (consisting of my_list1 and my_list2) is 'list' type.
What is the reason and how can I fix this?
My code:
xxxxxxxxxx1
my_list1 = [1, 3, 5]2
my_list2 = [0, 2, 4]3
4
merged = my_list1 + my_list2 # <--- this is list type5
print(type(merged)) # <class 'list'>6
7
result = merged.sort() # <--- this is NoneType8
print(result) # None9
print(type(result)) # <class 'NoneType'>10
1 answer
3 points
The sort() method is sorting in place and that's why the result is None.
Don't assign merged list to the new result variable, just sort it.
In your case it would be:
xxxxxxxxxx1
my_list1 = [1, 3, 5]2
my_list2 = [0, 2, 4]3
4
merged = my_list1 + my_list25
6
# sort merged list7
merged.sort()8
9
# print merged list as a result10
print(merged) # [0, 1, 2, 3, 4, 5]0 commentsShow commentsAdd comment
