EN
JavaScript - get domain name from given URL
8 points
In this article, we would like to show how to get a domain from a given URL in JavaScript.
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const getDomain = (url) => {2
const instance = new URL(url);3
const host = instance.hostname;4
return host.startsWith('www.') ? host.substring(4) : host;5
};6
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// Usage example:9
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console.log(getDomain('https://dirask.com')); // dirask.com11
console.log(getDomain('https://dirask.com/about')); // dirask.com12
console.log(getDomain('https://www.dirask.com')); // dirask.com13
console.log(getDomain('https://www.dirask.com/about')); // dirask.com
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const EXPRESSION = /^[a-z]+:\/\/(?:www\.)?([^:?#/]+)/; // domain in group expression2
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const getDomain = (url) => {4
const match = EXPRESSION.exec(url);5
if (match) {6
return match[1];7
}8
return null;9
};10
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// Usage example:13
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console.log(getDomain('https://dirask.com')); // dirask.com15
console.log(getDomain('https://dirask.com/about')); // dirask.com16
console.log(getDomain('https://www.dirask.com')); // dirask.com17
console.log(getDomain('https://www.dirask.com/about')); // dirask.comxxxxxxxxxx1
const EXPRESSION = /^[a-z]+:\/\/([^:?#/]+)/; // domain in group expression2
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const hasPrefix = (text, prefix) => {4
if (prefix.length > text.length) {5
return false;6
}7
for (let i = 0; i < prefix.length; ++i) {8
if (text[i] !== prefix[i]) {9
return false;10
}11
}12
return true;13
};14
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const getDomain = (url) => {16
const match = EXPRESSION.exec(url);17
if (match) {18
const host = match[1];19
if (hasPrefix(host, 'www.')) {20
return host.substring(4);21
}22
return host;23
}24
return null;25
};26
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// Usage example:29
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console.log(getDomain('https://dirask.com')); // dirask.com31
console.log(getDomain('https://dirask.com/about')); // dirask.com32
console.log(getDomain('https://www.dirask.com')); // dirask.com33
console.log(getDomain('https://www.dirask.com/about')); // dirask.com
