Bash - run one command after second one regardless of the result

In this short artlcle we would like to show how to run one command after second one regardless of the result using Bash.

Quick solution:

first_command; second_command

Practical examples

Example 1 - both commands success

In this example, we combine sleep and echo commands.

Bash command:

sleep 3; echo "Sleep command done!"

Output:

Sleep command done!

Explaination:

1. sleep command executes successfully suspends the calling shell script for 3 secons,

2. then echo command is executed printing text in the command line.

Example 2 - fail & success

In this example, we use ls and echo commands .

Bash command:

ls /path/to/unexisting/directory; echo "echo command done!"

Output:

ls: cannot access '/path/to/unexisting/directory': No such file or directory
ls command has failed and done!

Explaination:

1. ls command tries to list files under not existing directory and fails,

2. then echo command is run printing text in the command line.

See also

1. Bash - run one command after second one when first one is succeed and done

2. Bash - run one command after second one when first one fails