Bash - omit first argument from command line

In this article, we would like to show you how to omit first argument from command line in Bash.

In this example, we use "${@:2}" to capture all arguments passed from command line starting from the second argument. Then we iterate through all parameters using for loop and print them using echo command.

Example script.sh file:

xxxxxxxxxx

#!/bin/bash

​

for argument in "${@:2}"

do

    echo "$argument"

done

Run in the command line:

xxxxxxxxxx

./script.sh one two three

Output:

xxxxxxxxxx

two

three

1. Bash - capture all arguments passed from command line (regardless of their number)