[Edit]

JavaScript - compare array of objects to get min / max

1 contributors

2 contributions

0 discussions

0 points

Created by:

Eshaal-Wilkinson

774

In this article, we would like to show you how to compare an array of objects to get the min/max value of a property in JavaScript.

1. Minimum

Edit

In this example, we use reduce() method with ternary operator (?) to get an object with a minimum number property value from array of objects.

xxxxxxxxxx
 
var array = [
    { id: 1, number: 20 },
    { id: 2, number: 30 },
    { id: 3, number: 10 }
];
​
var min = array.reduce(function(previous, current) {
    return previous.number < current.number ? previous : current;
});
​
console.log(JSON.stringify(min)); // {"id":3,"number":10}

Auto running

2. Maximum

Edit

In this example, we use reduce() method with ternary operator (?) to get an object with a maximum number property value from array of objects.

xxxxxxxxxx
 
var array = [
    { id: 1, number: 20 },
    { id: 2, number: 30 },
    { id: 3, number: 10 }
];
​
var max = array.reduce(function(previous, current) {
    return previous.number > current.number ? previous : current;
});
​
console.log(JSON.stringify(max)); // {"id":2,"number":30}