EN
C# / .NET - Math.Min() method example
0 points
The Math.Min() function returns the smallest number from given numbers.
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using System;2
3
public class Program4
{5
public static void Main(string[] args)6
{7
int min = Math.Min(2, 5);8
Console.WriteLine( min); // 29
10
Console.WriteLine( Math.Min(1, 2)); // 111
Console.WriteLine( Math.Min(1.5, 2.0)); // 1.512
13
Console.WriteLine( Math.Min(2, Double.NaN)); // NaN14
}15
}| Syntax |
xxxxxxxxxx1 namespace System2 {3 public static class Math4 {5 // ...6 public static byte Min(byte val1, byte val2) { ... }7 public static decimal Min(decimal val1, decimal val2) { ... }8 public static double Min(double val1, double val2) { ... }9 public static short Min(short val1, short val2) { ... }10 public static int Min(int val1, int val2) { ... }11 public static long Min(long val1, long val2) { ... }12 public static sbyte Min(sbyte val1, sbyte val2) { ... }13 public static float Min(float val1, float val2) { ... }14 public static ushort Min(ushort val1, ushort val2) { ... }15 public static uint Min(uint val1, uint val2) { ... }16 public static ulong Min(ulong val1, ulong val2) { ... }17 // ...18 }19 } |
| Parameters | val1, val2 - values to compare. |
| Result |
Minimal It returns |
| Description | Min is a static method that takes number arguments and returns the smallest one value. |
xxxxxxxxxx1
using System;2
using System.Linq;3
4
public class Program5
{6
public static void Main(string[] args)7
{8
int[] array = new int[] { 1, 5, 2, 16, -5 };9
10
int min = array.Min();11
Console.WriteLine(min); // -512
}13
}xxxxxxxxxx1
using System;2
3
public class Program4
{5
static double Min(double[] array)6
{7
double result = Double.PositiveInfinity;8
foreach (double currentNumber in array)9
{10
if (result > currentNumber) result = currentNumber;11
}12
return result;13
}14
15
public static void Main(string[] args)16
{17
double[] numbersArray = new double[] { 1.4, 5.0, 2.2, 16.0, -5.0 };18
19
Console.WriteLine(Min(numbersArray)); // -520
}21
}