EN
C#/.NET - generate random double
7 points
In C#/.NET is possible to generate random double in few ways.
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Random random = new Random();2
int value = random.NextDouble();3
Console.WriteLine(value);Output:
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0.293478057856428Note: random value will be from 0 to 1 (exclusive upper bound).
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public static class RandomUtils2
{3
public static double generateDouble(double maxValue)4
{5
Random random = new Random();6
7
return maxValue * random.NextDouble();8
}9
}Example:
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int value = RandomUtils.generateDouble(100);2
Console.WriteLine(value);Output:
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44.2700352725899Note: random value will be from 0 to 100 (exclusive upper bound).
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public static class RandomUtils2
{3
public static double generateDouble(double minValue, double maxValue)4
{5
Random random = new Random();6
7
return minValue + (maxValue - minValue) * random.NextDouble();8
}9
}Example:
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int value = RandomUtils.generateDouble(10, 100);2
Console.WriteLine(value);Output:
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62.8952112574574Note: random value will be from 10 to 100 (exclusive upper bound).
