MS SQL Server - IIF() function example

In this article, we would like to show you IIF() function example in MS SQL Server.

Quick solution:

SELECT IIF(condition, if_true, if_false);

Practical examples

Example 1

In this example, we will check two conditions, the first one will return true, and the second one will return false.

Query:

SELECT IIF(1000 > 1, 'condition1_true', 'condition1_false') AS 'condition1_check';

SELECT IIF(1000 < 1, 'condition2_true', 'condition2_false') AS 'condition2_check';

Result:

Example 2

To show you how IIF() function works, we will use the following table:

Note:

At the end of this article you can find database preparation SQL queries.

In this example, we will display salary column from users table and salary_information which is created with IIF() function.

Query:

SELECT
    [salary],
    IIF([salary] > 6000, 'high_salary', 'average_salary') AS 'salary_information'
FROM [users];

Result:

Database preparation

create_tables.sql file:

CREATE TABLE [users] (
	[id] INT IDENTITY(1,1),
	[name] VARCHAR(50) NOT NULL,
	[surname] VARCHAR(50) NOT NULL,
	[department_id] INT,
    [salary] DECIMAL(15,2) NOT NULL,
	PRIMARY KEY ([id])
);

insert_data.sql file:

INSERT INTO [users]
	( [name], [surname], [department_id], [salary])
VALUES
	('John', 'Stewart', 1, '3512.00'),
	('Chris', 'Brown', 2, '1344.00'),
	('Kate', 'Lewis', 3, '6574.00'),
	('Ailisa', 'Gomez', NULL, '6500.00'),
	('Gwendolyn', 'James', 2, '4200.00'),
	('Simon', 'Collins', 4, '3320.00'),
	('Taylor', 'Martin', 2, '1500.00'),
	('Andrew', 'Thompson', NULL, '2100.00');