Java 8 - find max and min value in a List

In this article, we would like to show you how to find max and min values in a List in Java 8.

Quick solution

Max value:

List<Integer> integers = Arrays.asList(2, 3, 1);

int max = integers
        .stream()
        .mapToInt(x -> x)
        .max()
        .orElseThrow(NoSuchElementException::new);

System.out.println(max);  // 3

Min value: 

List<Integer> integers = Arrays.asList(2, 3, 1);

int min = integers
        .stream()
        .mapToInt(x -> x)
        .min()
        .orElseThrow(NoSuchElementException::new);

System.out.println(min);  // 1

1. Maximum

In this example, we use stream.max() method to find the maximum value of integers List.

import java.io.IOException;
import java.util.Arrays;
import java.util.List;
import java.util.NoSuchElementException;


public class Example {

    public static void main(String[] args) throws IOException {

        List<Integer> integers = Arrays.asList(2, 3, 1);

        int max = integers
                .stream()
                .mapToInt(x -> x)
                .max()
                .orElseThrow(NoSuchElementException::new);

        System.out.println("Max value = " + max);  // 3
    }
}

Output:

Max value = 3

2. Minimum

In this example, we use stream.min() method to find the minimum value of integers List.

import java.io.IOException;
import java.util.Arrays;
import java.util.List;
import java.util.NoSuchElementException;


public class Example {

    public static void main(String[] args) throws IOException {

        List<Integer> integers = Arrays.asList(2, 3, 1);

        int min = integers
                .stream()
                .mapToInt(x -> x)
                .min()
                .orElseThrow(NoSuchElementException::new);

        System.out.println("Min value = " + min);  // 1
    }
}

Output:

Min value = 1