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Java 8 - find max and min value in a List

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Created by:

Lennie-S

439

In this article, we would like to show you how to find max and min values in a List in Java 8.

Quick solution

Edit

Max value:

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List<Integer> integers = Arrays.asList(2, 3, 1);
​
int max = integers
        .stream()
        .mapToInt(x -> x)
        .max()
        .orElseThrow(NoSuchElementException::new);
​
System.out.println(max);  // 3

Min value:

xxxxxxxxxx
 
List<Integer> integers = Arrays.asList(2, 3, 1);
​
int min = integers
        .stream()
        .mapToInt(x -> x)
        .min()
        .orElseThrow(NoSuchElementException::new);
​
System.out.println(min);  // 1

1. Maximum

Edit

In this example, we use stream.max() method to find the maximum value of integers List.

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import java.io.IOException;
import java.util.Arrays;
import java.util.List;
import java.util.NoSuchElementException;
​
​
public class Example {
​
    public static void main(String[] args) throws IOException {
​
        List<Integer> integers = Arrays.asList(2, 3, 1);
​
        int max = integers
                .stream()
                .mapToInt(x -> x)
                .max()
                .orElseThrow(NoSuchElementException::new);
​
        System.out.println("Max value = " + max);  // 3
    }
}

Output:

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Max value = 3

2. Minimum

Edit

In this example, we use stream.min() method to find the minimum value of integers List.

xxxxxxxxxx
 
import java.io.IOException;
import java.util.Arrays;
import java.util.List;
import java.util.NoSuchElementException;
​
​
public class Example {
​
    public static void main(String[] args) throws IOException {
​
        List<Integer> integers = Arrays.asList(2, 3, 1);
​
        int min = integers
                .stream()
                .mapToInt(x -> x)
                .min()
                .orElseThrow(NoSuchElementException::new);
​
        System.out.println("Min value = " + min);  // 1
    }
}