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Java - compare long vs Long (primitive vs boxed long)

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Created by:

WGates

412

Quick solution:

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// import java.util.Objects;            
Long number1 = 100L;
long number2 = 100L;
​
boolean equals = Objects.equals(number1, number2);
System.out.println(equals); // true

Full example:

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import java.util.Objects;
​
public class java_compare_long_vs_Long {
​
    public static void main(String[] args) {
​
        {
            Long number1 = null;
            long number2 = 100L;
            System.out.println(Objects.equals(number1, number2)); // false
        }
​
        {
            Long number1 = 100L;
            long number2 = 100L;
            System.out.println(Objects.equals(number1, number2)); // true
        }
​
        {
            Long number1 = null;
            Long number2 = 100L;
            System.out.println(Objects.equals(number1, number2)); // false
        }
​
        {
            Long number1 = 100L;
            Long number2 = 100L;
            System.out.println(Objects.equals(number1, number2)); // true
        }
    }
}