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Bash - how to pass arguments to function

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Created by:

Teilsa

1315

This article will show you how to pass arguments to function in Bash.

Quick solution:

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#!/bin/bash
​
my_function(){
    # here we can refer to subsequent arguments using $1, $2 and $3
}
​
# number of argument
#             1     2      3    
my_function "one" "two" "three" 
​

Practical examples

Edit

A function that displays the argument given to it:

Edit

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#!/bin/bash
​
print_parameter(){
    echo $1
}
​
print_parameter "Dirask"
print_parameter "wiki for code"

Output:

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Dirask
wiki for code

A function that adds two numbers given as its parameters:

Edit

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#!/bin/bash
​
add_numbers(){
    echo $(($1 + $2))
}
​
add_numbers 1 2
add_numbers 10 13

Output:

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3
23

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