Java 8 - count unique objects eg Users and return Map<User, Integer> using Collectors.groupingBy

Quick solution:

import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.function.Function;
import java.util.stream.Collectors;

public class CountUsers {

    public static void main(String[] args) {

        List<User> users = new ArrayList<>();
        users.add(new User("Kate", 24)); // Kate - 1st time
        users.add(new User("John", 26));
        users.add(new User("Ann", 25));
        users.add(new User("Kate", 24)); // Kate - 2nd time
        users.add(new User("Kate", 24)); // Kate - 3rd time

        Map<User, Long> usersToCount = users.stream().collect(
                Collectors.groupingBy(
                        Function.identity(), Collectors.counting()
                )
        );

        usersToCount.forEach(
                (user, count) -> System.out.println(user + ", " + count)
        );
    }

    private static class User {
        private final String name;
        private final int age;

        public User(String name, int age) {
            this.name = name;
            this.age = age;
        }

        public String getName() {
            return name;
        }

        public int getAge() {
            return age;
        }

        @Override
        public boolean equals(Object o) {
            if (this == o) return true;
            if (o == null || getClass() != o.getClass()) return false;

            User user = (User) o;

            if (age != user.age) return false;
            return name != null ? name.equals(user.name) : user.name == null;
        }

        @Override
        public int hashCode() {
            int result = name != null ? name.hashCode() : 0;
            result = 31 * result + age;
            return result;
        }

        @Override
        public String toString() {
            return "User{" +
                    "name='" + name + '\'' +
                    ", age=" + age +
                    '}';
        }
    }
}

Output:

User{name='Ann', age=25}, 1
User{name='John', age=26}, 1
User{name='Kate', age=24}, 3