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C# / .NET - get random element from list

11 points
Created by:
Dharman
338

Random.Next method example

List<int> list = new List<int>();

list.Add(11);
list.Add(22);
list.Add(33);
list.Add(44);
list.Add(55);

Random random = new Random();

for (int i = 0; i < 10; ++i)
{
	int index = random.Next(list.Count);

	Console.WriteLine(list[index]);
}

Output:

33
44
11
55
55
55
22
11
11
11

References

  1. List<T> Class - Microsoft Docs
  2. Random Class - Microsoft Docs

C# / .NET - random

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