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JavaScript - check if number is odd (Vanilla JS)

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Created by:

Root-ssh

178170

In this short article, we would like to show how check if number is odd using JavaScript.

Quick solution:

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if (number % 2 !== 0) {
    // ...
}

Odd numbers:

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... -7  -5  -3  -1   1   3   5   7 ...

Practical example

Edit

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function isOdd(number) {
    return number % 2 !== 0;
}
​
​
// Usage example:
​
console.log( isOdd(0) );   // false
console.log( isOdd(1) );   // true      // odd
console.log( isOdd(2) );   // false
console.log( isOdd(3) );   // true      // odd
console.log( isOdd(4) );   // false
console.log( isOdd(5) );   // true      // odd
​
console.log( isOdd(-1) );  // true      // odd
console.log( isOdd(-2) );  // false
console.log( isOdd(-3) );  // true      // odd
console.log( isOdd(-4) );  // false
console.log( isOdd(-5) );  // true      // odd

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Alternative solution

Edit

In this section, you can find solution that uses bitwise operator.

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function isOdd(number) {
    return (number & 1) !== 0;
}
​
​
// Usage example:
​
console.log( isOdd(0) );   // false
console.log( isOdd(1) );   // true      // odd
console.log( isOdd(2) );   // false
console.log( isOdd(3) );   // true      // odd
console.log( isOdd(4) );   // false
console.log( isOdd(5) );   // true      // odd
​
console.log( isOdd(-1) );  // true      // odd
console.log( isOdd(-2) );  // false
console.log( isOdd(-3) );  // true      // odd
console.log( isOdd(-4) );  // false
console.log( isOdd(-5) );  // true      // odd