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JavaScript - sort array except one element
1 answers
0 points
How can I sort all values in array of object by key except one element?
For example, when I have an array:
xxxxxxxxxx1
var myArray = [2
{ key: 'd', value: 'value_D' },3
{ key: 'c', value: 'value_C' },4
{ key: 'e', value: 'value_E' },5
{ key: 'undefined', value: 'undefined' },6
{ key: 'b', value: 'value_B' },7
{ key: 'a', value: 'value_A' }8
];I want all the values to be sorted by key, except the undefined value, I want it to be at the beginning.
So the result would be:
xxxxxxxxxx1
[2
{ key: 'undefined', value: 'undefined' },3
{ key: 'a', value: 'value_A' },4
{ key: 'b', value: 'value_B' },5
{ key: 'c', value: 'value_C' },6
{ key: 'd', value: 'value_D' },7
{ key: 'e', value: 'value_E' }8
] 1 answer
0 points
You can use sort() method with custom compare function as its argument.
Practical example:
xxxxxxxxxx1
var myArray = [2
{ key: 'd', value: 'value_D' },3
{ key: 'c', value: 'value_C' },4
{ key: 'e', value: 'value_E' },5
{ key: 'undefined', value: 'undefined' },6
{ key: 'b', value: 'value_B' },7
{ key: 'a', value: 'value_A' },8
];9
10
myArray.sort(function(a, b) {11
if (a.key == b.key) return 0;12
if (a.key == 'undefined') return -1;13
if (b.key == 'undefined') return 1;14
if (a.key < b.key) return -1;15
if (a.key > b.key) return 1;16
return 0;17
});18
19
console.log(JSON.stringify(myArray, null, 4));Note:
This function sorts all items using regular sorting, except for items with
undefinedkeys, they are being placed at the beginning.
References
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