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Python - replace first n characters in string
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In this article, we would like to show you how to replace first n characters in string in Python.
Quick solution:
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text = "ABCD ABCD ABCD"2
n = 33
replacement = "XYZ"4
result = text.replace(text[0:n], replacement, 1)5
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print(result) # XYZD ABCD ABCD
In this example, we use replace() method to replace first n characters in the text string.
We use the following syntax:
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replace(old, new, count)Where:
old- is a substring to replace,new- is the replacement,count(optional argument) - is the number of times we want to replace the specified substring. You need to set it to1, so you won't replace anything but the first occurrence of the substring.
Practical example:
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text = "ABCD ABCD ABCD"2
n = 33
replacement = "XYZ"4
result = text.replace(text[0:n], replacement, 1)5
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print("Before: ", text) # ABCD ABCD ABCD7
print("After: ", result) # XYZD ABCD ABCDOutput:
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Before: ABCD ABCD ABCD2
After: XYZD ABCD ABCDNote:
If you don't set the
countargument, by default thereplace()method will replace all occurrences of theABCsubstring.Output:
xxxxxxxxxx1Before: ABCD ABCD ABCD2After: XYZD XYZD XYZD
