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MySQL - COUNT IF example

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Created by:

martineau

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In this article, we would like to show you COUNT IF statement example in MySQL.

Quick solution:

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SELECT COUNT(IF(condition, 1, NULL)) AS 'alias_name';

Note:

Go to this article to read more about IF() function and its parameters.

Practical example

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To show you how IF() function works, we will use the following users table:

Note:

At the end of this article you can find database preparation SQL queries.

Example

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In this example, we will count the number of users whose salary is high, average or low.

Query

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SELECT 
    COUNT(IF(`salary` = 6000, 1, NULL)) AS 'high_salary',
    COUNT(IF(`salary` = 4000, 1, NULL)) AS 'average_salary',
    COUNT(IF(`salary` = 2000, 1, NULL)) AS 'low_salary'
FROM
    `users`;

Result:

Database preparation

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create_tables.sql file:

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CREATE TABLE `users` (
    `id` INT(10) UNSIGNED NOT NULL AUTO_INCREMENT,
    `name` VARCHAR(50) NOT NULL,
    `surname` VARCHAR(50) NOT NULL,
    `department_id` INT(10) UNSIGNED,
    `salary` DECIMAL(15,2) NOT NULL,
    PRIMARY KEY (`id`)
);

insert_data.sql file:

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INSERT INTO `users`
    ( `name`, `surname`, `department_id`, `salary`)
VALUES
    ('John', 'Stewart', 1, '6000'),
    ('Chris', 'Brown', 2, '6000'),
    ('Kate', 'Lewis', 3, '4000'),
    ('Ailisa', 'Gomez', NULL, '4000'),
    ('Gwendolyn', 'James', 2, '4000'),
    ('Simon', 'Collins', 4, '4000'),
    ('Taylor', 'Martin', 2, '2000'),
    ('Andrew', 'Thompson', NULL, '2000');