JavaScript - check if array contains any element of another array

In this article, we would like to show you how to check if array contains any element of another array in JavaScript.

Quick solution:

// ONLINE-RUNNER:browser;

const array1 = ['a', 'b', 'c'];
const array2 = ['c', 'd', 'e'];

const result = array1.some((item) => array2.includes(item));

console.log(result); // true

Note:

Array includes() was introduced in ES6 (around 2016).

Alternative solution

In this section, we present an alternative solution that works in older web browsers and Node.js.

// ONLINE-RUNNER:browser;

const array1 = ['a', 'b', 'c'];
const array2 = ['c', 'd', 'e'];

const result = array1.some((item) => array2.indexOf(item) >= 0);

console.log(result); // true

See also

1. JavaScript - check if array contains value

References

1. Array.prototype.some() - JavaScript | MDN
2. Array.prototype.includes() - JavaScript | MDN
3. Array.prototype.indexOf() - JavaScript | MDN