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Java - get long max value

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168660

Short solution:

``````long MAX_VALUE = Long.MAX_VALUE;

System.out.println(MAX_VALUE);  // 9223372036854775807``````

Java Long max value is  `9223372036854775807`

Additionally short solution to get `long` min value:

``````long MIN_VALUE = Long.MIN_VALUE;

System.out.println(MIN_VALUE);  // -9223372036854775808``````

Java Long min value is `-9223372036854775808`

1. Alternative solutions

This section contains different approaches that lets to get max `Long` value.

• Using build-in `Long.MAX_VALUE`
• Using math power e.g. `(long) Math.pow(2, 63)`
• Using bit shifting e.g. `-1L >>> 1`
• Using bit shifting and not e.g. `~0L >>> 1`

Code example with above methods:

``````public class Example1 {

public static void main(String[] args) {

long MAX_VALUE = Long.MAX_VALUE;
System.out.println(MAX_VALUE);   // 9223372036854775807

long MAX_VALUE_2 = (long) Math.pow(2, 63);
System.out.println(MAX_VALUE_2); // 9223372036854775807

long MAX_VALUE_3 = -1L >>> 1;
System.out.println(MAX_VALUE_3); // 9223372036854775807

long MAX_VALUE_4 = ~0L >>> 1;
System.out.println(MAX_VALUE_4); // 9223372036854775807
}
}``````

Output:

``````9223372036854775807
9223372036854775807
9223372036854775807
9223372036854775807``````

2. Long overflow example

``````public class Example2 {

public static void main(String[] args) {

long MAX_VALUE = Long.MAX_VALUE;
long overflow = MAX_VALUE + 100;

System.out.println(overflow);  // -9223372036854775709
}
}``````

Output:

``-9223372036854775709``

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