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Java - convert String to long

4 points
Created by:
Marcin
15710

In Java, we can convert String to long in couple of different ways.

Short solutions:

// solution 1
long num1 = Long.parseLong("123"); // 123

// solution 2
Long num2 = Long.valueOf("123"); // 123

1. Using Long.parseLong()

public class Example1 {

    public static void main(String[] args) {
        String str = "123";
        long num = Long.parseLong(str);
        System.out.println(num); // 123
    }
}

Output:

123

2. Using Long.valueOf()

public class Example2 {

    public static void main(String[] args) {
        String str = "123";
        Long num = Long.valueOf(str);
        System.out.println(num); // 123
    }
}

Output:

123

3. String to long with sign + or -

public class Example3 {

    public static void main(String[] args) {

        // Long.parseLong() - returns long
        System.out.println(Long.parseLong("123")); // 123
        System.out.println(Long.parseLong("+123")); // 123
        System.out.println(Long.parseLong("-123")); // -123

        // Long.valueOf() - returns Long
        System.out.println(Long.valueOf("123")); // 123
        System.out.println(Long.valueOf("+123")); // 123
        System.out.println(Long.valueOf("-123")); // -123
    }
}

Output:

123
123
-123
123
123
-123

4. Example of java.lang.NumberFormatException

public class Example4 {

    public static void main(String[] args) {
        String str = "123a";
        long num = Long.parseLong(str);
        System.out.println(num);
    }
}

Output:

Exception in thread "main" java.lang.NumberFormatException: For input string: "123a"
	at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
	at java.lang.Long.parseLong(Long.java:589)
	at java.lang.Long.parseLong(Long.java:631)

Both methods:

  • Long.parseLong("123")
  • Long.valueOf("123")

will throw java.lang.NumberFormatException if we try to parse anything else then:
digits or '+', '-' as first character.

Java - String conversion

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