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C# / .NET - check if number is even
4
points
In this short article, we would like to show how check if number is even using C# / .NET.
Quick solution:
int number = 5;
if (number % 2 == 0)
{
// ...
}
Even numbers:
... -8 -6 -4 -2 0 2 4 6 8 ...
Practical example
using System;
public class Program
{
public static void Main(String[] args)
{
Console.WriteLine( NumberUtils.IsEven(0) ); // true // even
Console.WriteLine( NumberUtils.IsEven(1) ); // false
Console.WriteLine( NumberUtils.IsEven(2) ); // true // even
Console.WriteLine( NumberUtils.IsEven(3) ); // false
Console.WriteLine( NumberUtils.IsEven(4) ); // true // even
Console.WriteLine( NumberUtils.IsEven(5) ); // false
Console.WriteLine( NumberUtils.IsEven(-1) ); // false
Console.WriteLine( NumberUtils.IsEven(-2) ); // true // even
Console.WriteLine( NumberUtils.IsEven(-3) ); // false
Console.WriteLine( NumberUtils.IsEven(-4) ); // true // even
Console.WriteLine( NumberUtils.IsEven(-5) ); // false
}
}
public class NumberUtils
{
public static bool IsEven(int number)
{
return number % 2 == 0;
}
}
Alternative solution
In this section, you can find solution that uses bitwise operator.
using System;
public class Program
{
public static void Main(String[] args)
{
Console.WriteLine( NumberUtils.IsEven(0) ); // true // even
Console.WriteLine( NumberUtils.IsEven(1) ); // false
Console.WriteLine( NumberUtils.IsEven(2) ); // true // even
Console.WriteLine( NumberUtils.IsEven(3) ); // false
Console.WriteLine( NumberUtils.IsEven(4) ); // true // even
Console.WriteLine( NumberUtils.IsEven(5) ); // false
Console.WriteLine( NumberUtils.IsEven(-1) ); // false
Console.WriteLine( NumberUtils.IsEven(-2) ); // true // even
Console.WriteLine( NumberUtils.IsEven(-3) ); // false
Console.WriteLine( NumberUtils.IsEven(-4) ); // true // even
Console.WriteLine( NumberUtils.IsEven(-5) ); // false
}
}
public class NumberUtils
{
public static bool IsEven(int number)
{
return (number & 1) == 0;
}
}