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Java 8 - sort list with stream.sorted()
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In this article, we would like to show you how to sort lists with stream.sorted() in Java 8.
Natural order:
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List<String> list = Arrays.asList("C", "A", "D", "B");2
3
List<String> sorted = list4
.stream()5
.sorted()6
.collect(Collectors.toList());7
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System.out.println(sorted); // [A, B, C, D]Reverse order:
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List<String> sorted = list2
.stream()3
.sorted(Comparator.reverseOrder())4
.collect(Collectors.toList());5
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System.out.println(sorted); // [D, C, B, A]
In this example, we use stream.sorted() method to sort the list in alphabetical order and save the result as a new list - sorted.
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import java.io.IOException;2
import java.util.Arrays;3
import java.util.List;4
import java.util.stream.Collectors;5
6
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public class Example {8
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public static void main(String[] args) throws IOException {10
List<String> list = Arrays.asList("C", "A", "D", "B");11
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System.out.println("Original list: " + list); // [C, A, D, B]13
14
List<String> sorted = list15
.stream()16
.sorted()17
.collect(Collectors.toList());18
19
System.out.println("Sorted list: " + sorted); // [A, B, C, D]20
}21
}Output:
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Original list: [C, A, D, B]2
Sorted list: [A, B, C, D]Note:
By default, the
sorted()method usesComparator.naturalOrder().
In this example, we use stream.sorted() method with Comparator.reverseOrder() to sort the list in reverse order and save the result as a new list - sorted.
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package tmpOperations2;2
3
import java.io.IOException;4
import java.util.Arrays;5
import java.util.Comparator;6
import java.util.List;7
import java.util.stream.Collectors;8
9
10
public class Example {11
12
public static void main(String[] args) throws IOException {13
List<String> list = Arrays.asList("C", "A", "D", "B");14
15
System.out.println("Original list: " + list); // [C, A, D, B]16
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List<String> sorted = list18
.stream()19
.sorted(Comparator.reverseOrder())20
.collect(Collectors.toList());21
22
System.out.println("Sorted list: " + sorted); // [D, C, B, A]23
}24
}Output:
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Original list: [C, A, D, B]2
Sorted list: [D, C, B, A]