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C#/.NET - random double

7 points
Created by:
JustMike
3491

In C#/.NET is possible to generate random double in few ways.

1. Random double example

Random random = new Random();
int value = random.NextDouble();
Console.WriteLine(value);

Output:

0.293478057856428
Note: random value will be from 0 to 1 (exclusive upper bound).

2. Random double with max value example

public static class RandomUtils
{
	public static double generateDouble(double maxValue)
	{
		Random random = new Random();

		return maxValue * random.NextDouble();
	}
}

Example:

int value = RandomUtils.generateDouble(100);
Console.WriteLine(value);

Output:

44.2700352725899
Note: random value will be from 0 to 100 (exclusive upper bound).

3. Random double from range example

public static class RandomUtils
{
	public static double generateDouble(double minValue, double maxValue)
	{
		Random random = new Random();

		return minValue + (maxValue - minValue) * random.NextDouble();
	}
}

Example:

int value = RandomUtils.generateDouble(10, 100);
Console.WriteLine(value);

Output:

62.8952112574574
Note: random value will be from 10 to 100 (exclusive upper bound).
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